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adding option for single page count #3315

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Original file line number Diff line number Diff line change
Expand Up @@ -12,35 +12,48 @@ def initialize(search_context:, search_session:, current_document:)
end

def render?
@search_context.present? && (@search_context[:prev] || @search_context[:next]) && (@search_session['document_id'] == @current_document_id)
return false unless @search_session['document_id'] == @current_document_id

return true if total == 1
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I believe we need to check for @search_context here. Otherwise it will display on pages with no search context.


@search_context.present? && (@search_context[:prev] || @search_context[:next])
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is this effectively the same as:

Suggested change
return true if total == 1
@search_context.present? && (@search_context[:prev] || @search_context[:next])
@search_context.present?

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I am not sure, because maybe you can have a search_context but not have a :prev or :next?

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Right – my guess is that case (you have a context, but no prev or next) is the same thing as having a single result. But just a guess!

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Separately I have to remove the "|" separating the different sections, so that will be another commit.

end

##
# Displays "showing X of Y items" message.
#
# @return [String]
def item_page_entry_info
t('blacklight.search.entry_pagination_info.other', current: number_with_delimiter(count),
t('blacklight.search.entry_pagination_info.other', current: current_count,
total: number_with_delimiter(total),
count: total).html_safe
end

def link_to_previous_document(previous_document = nil, classes: 'previous', **link_opts)
return if total == 1

previous_document ||= @search_context[:prev]
link_opts = session_tracking_params(previous_document, count - 1, per_page: per_page, search_id: search_id).merge(class: classes, rel: 'prev').merge(link_opts)

link_to_unless previous_document.nil?, raw(t('views.pagination.previous')), url_for_document(previous_document), link_opts do
tag.span raw(t('views.pagination.previous')), class: 'previous'
end
end

def link_to_next_document(next_document = nil, classes: 'next', **link_opts)
return if total == 1

next_document ||= @search_context[:next]
link_opts = session_tracking_params(next_document, count + 1, per_page: per_page, search_id: search_id).merge(class: classes, rel: 'next').merge(link_opts)
link_to_unless next_document.nil?, raw(t('views.pagination.next')), url_for_document(next_document), link_opts do
tag.span raw(t('views.pagination.next')), class: 'next'
end
end

def current_count
total == 1 ? total : number_with_delimiter(count)
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Do we need a conditional here?

Suggested change
total == 1 ? total : number_with_delimiter(count)
number_with_delimiter(count)

end

private

def count
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Original file line number Diff line number Diff line change
Expand Up @@ -23,6 +23,17 @@
end
end

context 'when there is exactly one search result with no next or previous document' do
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What if someone goes directly to a show page without any session history. Will they still see this?

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After the most recent changes, I went directly to an item page url in a separate browser and that did not show the "1 of 1" content.

let(:search_context) { {} }
let(:search_session) { { 'document_id' => current_document_id, 'total' => '1' } }

it "renders single page count" do
expect(render.to_html).to include '<strong>1</strong> of <strong>1</strong>'
expect(render.css('span.previous').to_html).to be_blank
expect(render.css('span.next').to_html).to be_blank
end
end

context 'when there is next and previous' do
let(:search_context) { { next: next_doc, prev: prev_doc } }
let(:prev_doc) { SolrDocument.new(id: '777') }
Expand Down