Question: How does it handle output?

[purefan]

Hi!

One of the things I need to do is run webpack and watch for file changes, another I need to do is fire up dynamodb local, another one is to keep an electron app running... all of these spit out debugging information that I may need.

Ideally, I would use your plugin and combine all their output in one single stdout that I can prefix with an identifier:

[electron] debug from the app...
[webpack] reloaded stuff
[dynamodb] requested record X

is this something I can do with your plugin? (and if so, how?)

Thanks for your hard work!

[juanfran]

Hi!, sorry but currently you can't do it but maybe is possible to add the feature. I'm going to try these days to see if it's possible.

[purefan]

Thanks @juanfran ! and again, thanks for all your work

[juanfran]

Hi! I haven't got an easy & clean solution to do this (yet¿), but I have an idea without changing this plugin.

function hook_stdout(message) {
  var old_write = process.stdout.write

  process.stdout.write = (function(write) {
      return function(string, encoding, fd) {
          arguments[0] = message + ': ' + arguments[0];
          write.apply(process.stdout, arguments);
      }
  })(process.stdout.write)

  return function() {
      process.stdout.write = old_write
  }
}

gulp.task('task1', function(cb) {
  hook_stdout('task example');
  
 // example gulp task
});

with this anything inside the task1 will log this "task example: example text from webpack plugin", this is what you need?