Intransitive card game.

[Carreau]

There are games know as "intransitive", basically A > B > C > A, so thre can't be any "winner". It would be good to figure out how to make this automatically for trading cards after giving them statistics, like attack/defence.

[Carreau]

Talking with @danielballan, he suggested putting the cad on a cycle, and finding way to count the number of nodes to go from A to B in clockwise and anticlockwise direction, and the smallest one give us which card wins.

[Carreau]

There might be also some things we can use out of dobble game that uses projective plane math to make sure two cards only have a single symbol in common.

[danielballan]

I guess rock--paper-scissors is an example of such a game. One useful train of thought may be to consider how to extend that to N objects in a graphical way.

[Carreau]

what about vector product if two object are on a 2D plane ?

…

On Sun, Jul 17, 2022 at 10:08 Dan Allan ***@***.***> wrote: I guess rock--paper-scissors is an example of such a game. One useful train of thought may be to consider how to extend that to N objects in a graphical way. — Reply to this email directly, view it on GitHub <#2 (comment)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AACR5T4P5RX2YCUMWNTI4S3VUQOVLANCNFSM53YG37JQ> . You are receiving this because you authored the thread.Message ID: ***@***.***>

[danielballan]

Yeah, that seems doable mentally. How does it determine which card “wins”?

[Carreau]

How does it determine which card “wins”?

Whatever is positive. As A^B = - B^A as long as you have a convention to consider your card first that should be good.

[danielballan]

That makes sense!

If each card gets a 2D coordinate there are several games that might be possible: battleship is one.