How do I use an async function?

[Xalwer]

# vc is disnake.VoiceClient

def after(error):
    await vc.disconnect()

vc.play(after=after)

How do I use await vc.disconnect()?

[ironman9356]

Hi,
First you should know what async and await are.
In simple terms:

"async and await make promises easier to write"

async makes a function return a Promise

await makes a function wait for a Promise

from here

So whenever you are using an await you must make sure its an async function
In this case your after function must be async because its making a "promise" to do things in the function and the await inside the function returns the "promise"

Example:
You are making a "promise" to the program that your bot will disconnect after some time. So you make an async function and make the function return the "promise" of bot disconnect. The await will return the "promise".
I hope this helps

[Xalwer]

the problem is I can't pass the async function as an argument to vc.play(after=)

this code will throw an error:

# vc is disnake.VoiceClient

async def after(error):
    await vc.disconnect()

vc.play(after=await after)

In general, I need the bot to simply disconnect after the end of the audio track.

Thanks for the answer.

[Sharp-Eyes]

I personally find something like this a fairly elegant solution:

event: asyncio.Future[None] = asyncio.Future()

def after(exc: Exception | None):
    event.set_exception(exc) if exc else event.set_result(None)

vc.play(src, after=after)
await event  # wait until the player is done

await vc.disconnect()

The trick is to use something you can synchronously set a flag on and asynchronously wait for that flag to be set, which is something asyncio.Future is particularly well-suited for.